Question

a bike accelerates uniformly from rest to velocity of 10 m/s over a distance of 50m. determine the acceleration of the bike.​

Answer 1

Given:-

• Initial velocity (u) = 0m/s

• Final velocity (v) = 10m/s

• Distance traveled (s) = 50m.

To Find:-

• Aceleration of the bike (a).

Solution:-

By using 3rd equation of motion

→ v² = u² + 2as

Substitute the value we get

→ 10² = 0² + 2×a ×50

→ 100 = 0 + 100×a

→ 100 = 100×a

→ a = 100/100

→ a = 1m/s².

∴ The acceleration of the bike is 1m/s².

Answer 2

Explanation :-

✔Given :-

• Initial velocity (u) = 0m/s
• Final velocity (v) = 10m/s
• Distance(s) = 50m

✔ To Find :-

• The acceleration(a) of the bike.

✔ Solution :

Applying 3rd equation of motion,

v² = u² + 2as

[ Substituting the values ]

=> 10² = 0² + 2 × a × 50

=> 100 = 100a

=> a = 100/100

=> a = 1 m/s².

✔ Hence,

• The acceleration of the bike is 1m/s².

✔ Verification :-

v² = u² + 2as

[ Putting values ]

=> 10² = 0² + 2 × 1 × 50

=> 100 = 2 × 50

=> 100 = 100

✔ Hence Verified.