Question

A bike has a uniform acceleration of 6 m/s². What distance will it cover in 25 seconds after start?
1875 m
1800 m
1765m
1935 m​

Answer 1

Answer:

1875 m

Step-by-step explanation:

Given that

The bike is initially at rest;

initial velocity (u) = 0 ms-1

Acceleration (a) = 6 ms^-2

Time period (t) = 25 s

Find out

What distance will it cover in 25 s after start

Formula

As per the second motion equation, s = ut+1/2 at^2

Therefore, the total distance covered by the bike (s) = 0 * 10m + 1/2 (6ms^-2)(25s)^2

= 1875 meters

Therefore, the bike will cover a distance of 1875 meters after 25 seconds.

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