a bike is moving with a speed of 10 m sec it suddenly gets stopped by applying breaks .if the negative acceleration produced in the bike is 0.5m/sec2 then calculate the distance covered by bike after apply break
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Hey mate here is ur ans
we take here -a as it is negative acceleration or retardation
we know that v=u-at
=>0=u-0.5*10=>u=5m/s
we also know that
s=ut-1/2at²
s=5*10-1/2*0.5*10=50-2.5=47.5m
hope it helps you
we take here -a as it is negative acceleration or retardation
we know that v=u-at
=>0=u-0.5*10=>u=5m/s
we also know that
s=ut-1/2at²
s=5*10-1/2*0.5*10=50-2.5=47.5m
hope it helps you
nirman768:
thanks
wlcm
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