Question

A bike is moving with a uniform velocity of 54 km/h. when the rider applies the breaks , it comes to rest in 10 seconds. what is the the acceleration produced by the brakes?

Answer 1

Answer:

a = -1.5m/s²

Explanation:

GIVEN:-

u = 54 Km/hr¹

= 54×5/18

= 15m/s¹

V = 0 m/s¹

t = 10sec

WE NEED TO FIND THE ACCELERATION OF THE BIKE....

a = ?

SOLUTION:-

We know that:-

v = u + at

0 = 15 + a10

0 = 15 + 10a

-15 = 10a

-15/10 = a

So, a = - 1.5m/s²

EXTRA INFORMATION:-

• Here, acceleration is negative because the final velocity; which is greater than the initial velocity is zero.
• When the acceleration is negative, it is known as retardation.
• Here, in the above given answer, v refers to the final velocity, u refers to initial velocity, a refers to acceleration and t refers to time.
• Here, we have used the first equation of the motion is :- v = u + at. The other equations of the motion are:-
• 2nd equation:- S = it + ½ at² where s refers to the distance.
• 3rd equation:- v² - u² = 2as