a bike is moving with a velocity of 5 km per hour after applying brake it stop in 5 second calculate the force applied by breaks mass of motorcycle and Ryder is 100 kg
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Initial velocoty (u) of the bike = 5km/h = 25/18m/s
Final velocity = 0 (as the bike cems to rest)
time taken = 5s
Acceleration = (v-u)/t
= (0-25/18) / 5
= -(25/18)/5
= - 5/18 m/s^2
Mass of the bike and rider = 100kg
Force = mass× acceleration
= (100)(-5/18)
= -27.77 N
Hence, the force applied by the brakes was 27.77N.
Here, the negative sign represnts force in opp. direction.
Final velocity = 0 (as the bike cems to rest)
time taken = 5s
Acceleration = (v-u)/t
= (0-25/18) / 5
= -(25/18)/5
= - 5/18 m/s^2
Mass of the bike and rider = 100kg
Force = mass× acceleration
= (100)(-5/18)
= -27.77 N
Hence, the force applied by the brakes was 27.77N.
Here, the negative sign represnts force in opp. direction.
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