Question

A bike is moving with a velocity of 90 km/hr. After applying break it stop in5sec. Calcute thr force applied by breaks.mass of motorcycle and rides is 200kg

Answer 1

your questions answer in easy explanation.

Answer 2

Given,

•Mass of motorcycle and rider m = 200 Kg

•Initial velocity u = 90 Km/h-1 =

90×5/18

•Final Velocity of motor cycle v = 0 •Time (t) = 5s

acceleration (a) = (u-v)/t

force (f )= ma

F =(200 ×(0-25))/ 5 =-1000N