A bike is moving with a velocity of 90 km/hr. After applying break it stop in5sec. Calcute thr force applied by breaks.mass of motorcycle and rides is 200kg
Answers
Answered by
1
your questions answer in easy explanation.
Attachments:
Answered by
0
Given,
•Mass of motorcycle and rider m = 200 Kg
•Initial velocity u = 90 Km/h-1 =
90×5/18
•Final Velocity of motor cycle v = 0 •Time (t) = 5s
acceleration (a) = (u-v)/t
force (f )= ma
F =(200 ×(0-25))/ 5 =-1000N
Similar questions