Question

A bike is travelling at 10m/s. If it is accelerating at 2m/s (square) ,what is its velocity after 5 s?

Answer 1

Explanation:

Given that ,

Initial Velocity u = 10 m/s

Acceleration a = 2 m/s2

Time taken t = 5 s

By the Newton's equation of motion

$v = u + at$

$= 10 + 2 \times 5$

$= 10 + 10$

= 20 m/s Ans

Answer 2

Answer:

• Final velocity is 20 m/s.

Given:

• Initial velocity = 10 m/s
• Acceleration = 2 m/s²
• Time taken = 5 sec

Explanation:

$\rule{300}{1.5}$

Here, we are given that a bike is travelling with the initial velocity of 10 m/s accelerating at the rate of 2 m/s². We are asked to find it's final velocity after 5 sec.

From first kinematic equation we know,

$\longrightarrow{\sf{v\ =\ u\ +\ at}}$

Here,

• v denotes final velocity
• u denotes initial velocity
• a denotes acceleration
• t denotes time taken

Substitute the values,

$\longrightarrow{\sf{v\ =\ 10\ +\ 2 \times 5}} \\ \\ \\ \longrightarrow{\sf{v\ =\ 10\ +\ 10}} \\ \\ \\ \longrightarrow{\sf{v\ =\ 20\ m/s}}$

∴ The final velocity of the bike is 20 m/s.

$\rule{300}{1.5}$