Question

A bike is travelling at a uniform speed of 90 k/h. Calculate the distance cover in 5 second?​

Answer 1

Explanation:

.04 km because in 1 minutes there is 60 seconds so in hours there is 3600 seconds

Answer 2

Answer:

$\green{ \boxed {\sf \: distance \: covered \: is \: \: d = 125 \: m}} \:$

Explanation:

Given,

$\odot \sf \: Uniform \: speed \: , v = \: 90 \: kmh^{-1} \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{90 \times 1000}{3600} \: m {s}^{ - 1} \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 25 \: m {s}^{ - 1} \\</p><p> \odot \sf \: Time, t = 5 s \\ \\ \odot \sf \: distance \: \: d = to \: find$

We know that,

$\bf \: distance \: (d) = speed(v) \times time(t) \\ \sf \implies \: d = vt \\ \sf \implies \: d = 25 \times 5 \\ \sf \implies \:d = 125 \: m \\ \\ \therefore \: \green{ \boxed {\sf \: distance \: covered \: is \: \: d = 125 \: m}}$