Question

A bike is travelling at a uniform speed of 90 k/h. Calculate the distance cover in 5 second?​

Answer 1

★ Given That :

• ‣ Uniform Speed of Bike (S) = 90km/h
• ‣ Time taken by Bike (T) = 5 seconds

★ Need to Find :

• The Distance cover in 5sec by Bike ?

✪ Formula Used Here :

• ➻ D = S × T

☢ Where :

• ↠ D = Distance
• ↠ S = Speed
• ↠ T = Time

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✇ Conversion Needed :

◆ Uniform Speed of Bike (S) = 90km/h :

• ➳ S = 90km/h into m/s
• ➳ S = 90 × 5 / 18
• ➳ S = 25m/s

✧ Putting Value in Formula :

• ⇢ Distance = Speed × Time
• ⇢ Distance = 25 × 5
• ⇢ Distance = 125 Metres

✠ Therefore :

• » The Distance cover in 5s by bike is 125m.

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Answer 2

u=0

v=90km/h=90×5/18 m/s=25 m/s

t=5s

s=?

a=?

v=u+at

=>25=0+a.5

=>5a=25

=>a=5

acceleration =5 m/s²

s=ut+1/2at²

=>s=0.5+1/2.5.(5)²

=>s=1/2×5×25

=>s=62.5

distance=62.5 m