A bike moves with a velocity of 90km/hr. After the biker applies brake, the bike stops in 5 seconds. Calculate the force applied by the brakes. Given the combined mass of the biker and the bike is 200 kg.
Answers
Answered by
3
Initial velocity, u = 90 km/h or 25 m/s.
Final velocity, v = 0 bcoz it stops
Mass = 200 kg
Now, force exerted by the brakes will be the acceleration they produce to stop the motorcycle.
Therefore we will use the formula, v = u+at
v= u+ at
0= 25 + a * 5
-25= a* 5
Therefore, force exerted by the brakes is -1000 N to stop the motorcycle.
-5= a
Now, force exerted = product of mass and acceleration
= 200* -5
= -1000 N
Answered by
3
velocity = 90km/hr
time = 5 seconds
mass of the biker and the bike = 200kg
force = ?
F = ma
F = m(v/t)
F = 200(90/5)
F = 3600 newton/ meter
jeya11:
i hope it would be helpful for u
is the answer crct
wait what im confused
wat
i think first we have to use u=v+at and then force=mass*accelaration
acceleration*
this will be better than that i think so
ya but we got different answers thats why
ask the questioner about the crct answer
ok thnx
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