A bike moving ahead on a straight highway passes a shop with a constant velocity of 18 m/s . After 5 seconds, it begins accelerating uniformly. 20 seconds after passing the shop, the bike's velocity is 63 m/s . Find the bike's speed 14 seconds after passing the shop.
Answers
Given : A bike moving ahead on a straight highway passes a shop with a constant velocity of 18 m/s.
After 5 seconds, it begins accelerating uniformly
20 seconds after passing the shop, the bike's velocity is 63 m/s.
To Find : the bike's speed 14 seconds after passing the shop
Solution:
A bike moving ahead on a straight highway passes a shop with a constant velocity of 18 m/s.
Hence velocity also after 5 secs = 18 m/s
After 5 seconds, it begins accelerating uniformly = a
20 seconds after passing the shop, the bike's velocity is 63 m/s.
=> 20 - 5 = 15 secs
V = u + at
=> 63 = 18 + a(15)
=> 45 = 15a
=> a = 3 m/s²
bike's speed 14 seconds after passing the shop
14 - 5 = 9 secs
V = U + at
=> V = 18 + 3(9)
=> V = 45 m/s
bike's speed 14 seconds after passing the shop = 45 m/s
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