Question

..
A bike moving on the positive x-axis with a uniform velocity of 4m/s passes a car at a signal. The
bike (which is moving with 4m/s) is overtaken by the car moving uniformly at 12m/s. The bike
accelerates uniformly and overtake the car after travelling 200 metres away. Find the velocity of
the bike and its acceleration and also find the time of travel.

Answer 1

Final Velocity of bike =  20 m/s , acceleration = 24/25 m/s² and  Time of travel = 50/3 sec

Step-by-step explanation:

Bike initial Speed = 4 m/s

acceleration =  a

time  =  t   after which bike overtake car

Car Speed = 12 m/s

Distance Covered by car = 12t  = 200 m

=> t = 50/3  sec

Distance covered by bike  =  4t + (1/2)at²

= 4(50/3)  + (1/2)a(50/3)²

= (50/6) ( 8  + a50/3)

(50/6) ( 8  + a50/3)  = 200

=> 8 + 50a/3  = 24

=> 50a/3  = 16

=> a  = 48/50

=> a = 24/25  m/s²

Final Velocity of bike =   4  +  (24/25)(50/3)

= 4 + 16

= 20  m/s

Learn more:

A ball starts moving eastward with speed 35 m/s. An acceleration of ...

https://brainly.in/question/8968403

a particle initially at rest moves along x axis. it is subjected to an ...

https://brainly.in/question/4598640