Question

A bike of mass 180 kg is moving with a uniform velocity of 126 km/h. The force required to stop the bike in 18 sec.

Answer 1

Answer:

a= 0-126 /18

a= -126/18

a = -7

force = mass × acceleration

f = 180×-7

f =-1260

Answer 2

Given :-

• Mass of bike = 180 kg.
• Initial velocity = 126 km/h
• Final velocity = 0 km/ h
• Time = 18 sec

To find :-

• Force required

Formula applied :-

${\boxed{\sf{Force = Mass \times Acceleration}}}$

${\boxed{\sf{ Acceleration = \frac{Final \: Velocity- Initial \: Velocity}{ Time} }}}$

Solution :-

${\sf{\implies{Force = Mass \times Acceleration }}}$

${\sf{\implies{Force = M \times \cfrac{ v-u}{ t } }}}$

Here

• v = Final Velocity
• u = Initial Velocity
• t = time

Force Required :-

${\sf{\implies{Force = 180 \times \cfrac{ 0-126}{ 18} }}}$

${\sf{\implies{Force = 180 \times - \cfrac{ 126}{ 18} }}}$

${\sf{\implies{Force = 180 \times { -7} }}}$

${\sf{\implies{Force = - 1260 \: N}}}$

Here Force required is -1260 Newton.