Science, asked by ggbx8038, 1 month ago

A bike of mass 200 kg is travelling 36 kilometre per hour. The is brought to a rate after a distance cover 40 mitre find the retradation and force applied

Answers

Answered by kalpnajha1986kp
1

Answer:

Your answer is here dear mate :-

Mass = m = 200kg

intial velocity = u = 36km/hr = 36000m/

3600s=10m/s

k

final velocity = v = 0 km/hr = Om/s

distance =s= 10m

acceleration = a = ?

Force F=?

v-u 2as

(0)3-(10) 2(a)(10)

0-100 20a

-100/20=a

-5 m/s a

F ma

F 200kg x -5m/s2

Fa-1000kgm/s

F-1000N

F -10 N

F=-1 KNN

(here minus sign shows that force

acting apposite of objects motion)

so force acting on the car is -1 kilo

newton. or -1000 newton

Hope it helps !!!

pls mark me brainliest

have an nice day !!!

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