Question

A bike reduce by 20% in a sale. If its sale price was $520, what was the original price.

Answer 1

SOLUTION:

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ANSWER:-

• Original price = 416.

GIVEN:-

• Discount % = 20%
• Selling price = $520

TO FIND:-

• Cost price or original price?

SOLUTION:-

Let the cost price be x

CASE I:

FORMULA TO FIND DISCOUNT PRICE :-

$\boxed{ \sf Discount \: price = \frac{Discount\%}{100} = \dfrac{x}{Selling \: price} }$

SOLVING BY APPLYING THE FORMULA:-

$\rightarrow \sf \dfrac{20}{100} = \dfrac{x}{520}$

${\rightarrow \sf 100 \times x = 20 \times 520(Cross \: multiplication)}$

$\rightarrow \sf 100x = 10400$

$\rightarrow \sf x = \dfrac{10400}{100}$

$\rightarrow \sf 104 \: dollers.$

CASE II

Original price = selling price - discount price.

Original price = 520$ - 104$.

Cost price = 416.

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Answer 2

Question:-

1. A bike reduce by 20% in a sale. If its sale price was $520, what was the original price.

Required answer:-

• $416 is the original price (cost price) required

To find,

• The original price or you can take it as Cost Price (C.P)

Given that:-

• Discount percent = 20%
• Selling price (S.P) = $520

Formula to be used,

$\rm Discount=\dfrac{Discount \%}{100} = \dfrac{x}{S.P}$

Solution:-

• To find the answer we have to do it in two different cases

Case I :-

⇢ $\rm\dfrac{20}{100}=\dfrac{x}{520}$

⇢ $\rm 100 \times x = 20 \times 520$

⇢ 100 x = 10400

$\rm x=\dfrac{10400}{100}$

⇢ x = $104

Case II :-

    Cost price = Selling price - discount

• Let Cost price be (x)

x = $520 - $104

x = $416

Therefore, the original price is $416