Question

A bike rider accelerates uniformly at 2.0 m/s2 for 10.0 seconds. If the rider starts from rest, calculate the distance traveled during this time.

Answer 1

Explanation:

The distance is =7m

Explanation:

Apply the equation of motion

s(t)=ut+12at2

The initial velocity is u=0ms−1

The acceleration is a=2ms−2

Therefore, when t=3s, we get

s(3)=0+12⋅2⋅32=9m

and when t=4s

s(4)=0+12⋅2⋅42=16m

Therefore,

The distance travelled in the fourth second is

d=s(4)−s(3)=16−9=7m