Question

A Bike rider starts at 60 km/hr and he increases his speed in every 2 hours by 3 km/hr. then the maximum distance covered by him in 24 hours is

Answer 1

Answer:

Hii here is your answer

Step-by-step explanation:

Given: u= 60km/hr

t= 24hrs

v= it's speed increases 3 km/hr in every 2 hr. so, 24/2×3+60= 96km/hr

acceleration= v-u/t

= 96-60/24=3/2km/hr square

distance=ut+1/2at×t

=60×24+1/2×3/2×24×24

=84+144

=238 km

So, distance covered in 24 hours is 238km

Answer 2

Answer:

u= 60 km/h = 16.7 m/s

t = 24 h = 86400 h

a = (3 km/h) / (2 h) = 0.0012 m/s

s = ut + 1/2 at^2

= 16.7 x 86400 + 1/2 x 0.0012 x 86400^2

= 5921856

or, s = 5.9 x 10^6