Question

A bike riding at 22.4 m/s skids to come a halt in 2.55s. Conclude the skidding distance of the bike​

Answer 1

Answer:

28.92m

Explanation:

u= 22.4 m/s  

v= 0 m/ s  

a=?  

t= 2.55 sec

 

so, a= 0- 22.4/2.55  

=> a= -8.7 m/s^2  

s= ut+ 1/2 at^2  

= 22.4* 2.55+ 1/2 (-8.7)*2.55^2  

= 57.12 - 28.2  

= 28.92 m