Question

A bike riding at 22.4 m/s skids to come to a halt in 2.55 s. Conclude the skidding distance of the bike.​

Answer 1

Answer:

Here, initial velocity, u=22.4m/s and final velocity, v=0 m/s

Time taken by car to stop t=2.55s

If a be the acceleration.

Using formula v=u+at,

0=22.4+a(2.55)

We get a=−8.78m/s2 (negative signs means deceleration of car)

If d be the distance traveled by car.

Using formula v2 - u2 = 2ad

0^2 - (22.4)2 = 2( - 8. 78 d)

⟹ d=28.6m

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Answer 2

Explanation:

Here, initial velocity, u=22.4m/s and final velocity, v=0 m/s

Time taken by car to stop t=2.55s

If a be the acceleration.

Using formula v=u+at,

0=22.4+a(2.55)

We get a=−8.78m/s

2

(negative signs means deceleration of car)

If d be the distance traveled by car.

Using formula v

2

−u

2

=2ad

0

2

−(22.4)

2

=2(−8.78)d

⟹ d=28.6m