Question

A bike riding at 22.4 m/s skids to come to a halt in 2.55 s. Conclude the skidding distance of the bike.

Answer 1

u= 22.4 m/s

v= 0 m/ s

a=?

t= 2.55 sec

a= 0- 22.4/2.55

=> a= -8.7 m/s^2

s= ut+ 1/2 at^2

= 22.4* 2.55+ 1/2 (-8.7)*2.55^2

= 57.12 - 28.2

= 28.92 m

Answer 2

Solution.

$<b><u>initial velocity, u= 22.4 m/s$

final velocity, v= 0 m/ s

Acceleration, a=?

time, t= 2.55 sec

so, a= 0- 22.4/2.55

=> a= -8.7 m/s^2

now, s= ut+ 1/2 at^2

= 22.4* 2.55+ 1/2 (-8.7)*2.55^2

= 57.12 - 28.2

= 28.92 m

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