Question

a bike riding at 22.4m/s skids to come to a halt in 2.55s.Conclude the skidding distance of the bike.

Answer 1

A bike is traveling at a speed of  22.4 m/s and skids to a stop in 2.55 s. So we have following information:
Initial speed of the car i.e  u= 22.4 m/s
Final speed of the car  i.e.  v=0 m/s 
Time taken to come to stopping position  t= 2.55 sec
We wish to determine an acceleration (which is in fact a retardation) a=?
We have equation of the motion
V=u+at
0=22.4+2.55*a
-2.55a=22.4
a=22.4/-2.55
=-8.784 ms square
v square= u square+2as
0=(22.4)square+28s(-8.784)
-501.76=-17.568 s
s=28.56m