Question

A bike staring from rest has a uniform acceleration of 0.2 m/s2. Calculate the speed of the bike after 2.5 mins​

Answer 1

Speed of bike after 150 sec = 30 m/s

Step-by-step explanation:

Given:

• Initial velocity of bike = u = 0

• Acceleration of bike = a = 0.2 m/s²

• Time = 2.5 minutes = 150 sec

To find:

• Speed of bike after 150 sec = v = ?

Solution:

The equation of motion that connects all the given data is the First Equation of motion.

v = u + at

⇒ v = 0 + 0.2(150)

⇒ v = 0 + 30

⇒ v = 30 m/s

$\therefore$ The speed of bike after 150 sec = 30 m/s

Answer 2

Answer: 30 m/s

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Explanation:

Acceleration(a) = 0.2 m/s^2

Time (t) = 2.5 min =2.5 *60 s = 150 s

Initial velocity (u) = O m/s ---> starts from rest

Now,

v= u +at

= 0 + 0.2 * 150

=30 m/s