Question

A bike starts from rest on a horizontal road with
constant acceleration. After covering distance D it
has velocity v. Its velocity just after covering
was​

Answer 1

The velocity of the biker just after covering (D/4) is $\dfrac{v}{2}$.

Explanation:

Initial speed of the bike is 0 as it is at rest. If it cover a distance D, its velocity is given by :

$v^2-u^2=2aD\\\\v=\sqrt{2aD}$

Let V is the velocity of the biker just after covering (D/4). Again using third equation of motion, we get :

$V^2=2a(\dfrac{D}{4})\\\\V=\sqrt{2a\dfrac{D}{4}}\\\\V=\dfrac{1}{2}\times \sqrt{2aD}\\\\V=\dfrac{v}{2}$

So, the velocity of the biker just after covering (D/4) is $\dfrac{v}{2}$.

Learn more,

Kinematics

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