Question

A bike starts from rest on a horizontal road with constant acceleration. After covering distance D it has velocity v. Its velocity just after covering D/4 was​

Answer 1

Answer:

v' = v/2

Explanation:

By using the 3rd equation:

2as=v^2 - u^2

Since u=0

So according to the question

V= -/2aD ........ (1)

Now let v' be the velocity when it cover distance D/4

So v'= -/2aD/4 = -/ aD/2

Now comparing it with the first equation

v' = v/2

Hope this helps