Question

A bike takes 6 s to accelerate from 10 m/s to 14 m/s. The mass of the bike and its rider is 90 kg. Find the net force and the final momentum of the bicyclist.

Answer 1

Answer:

acc = (14-10) / 6

= 4/6

= 2/3

force applied = mass × Acc

= 90 × 2/3

= 60 N

Final momentum = Mass × final velocity

= 90 × 14

= 1260

Answer 2

The net force is $60N$ and the final momentum is $1260kgm/s$

Step-by-step explanation

Given data:

initial velocity of the bike$=10m/s$

Final  velocity of the bike$=14m/s$

The time taken to accelerate $=6s$

mass of the bike and its rider$=90kg$

To find:

We must find the net force and the final momentum of the bicyclist.

Formula to be used:

• $F=m(v-u)/t$

where $F=$force

$m=$ $90kg$ (mass)

$u=10m/s$ (initial velocity)

$v=14m/s$ (final velocity)

• $p=mv$

where: $p=$momentum

$m=90kg$ mass

$v=14m/s$ (final velocity)

Solution:

Using the formula: $F=m(v-u)/t$ we can find the net force.

$F=90(14-10)/6$

$F=(90$×$4)/6$

$F=360/6$

$F=60N$

Using the formula: $p=mv$ we can find the final momentum

$p=90$×$14$

$p=1260kgm/s$

Therefore the net force of the bicyclist is $60N$ and the final momentum of the bicyclist is $1260kgm/s$

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