Question

a bike travels with an acceleration 1m/s sq and covers distance 25 m from its initial velocity and find the final velocity please give correct answer and fast because it is very important ​

Answer 1

Acceleration (a) = 1m/s^2

Distance (s) = 25m

Initial velocity (u) = 0m/s

Final velocity (v) = ??

v^2 = u^2 + 2as

v^2 = 0^2 + 2 × 1 × 25

v^2 = 2 × 25

v^2 = 50

v = √50

v = 7.07m/s.

Therefore, Final velocity = 7.07m/s

Answer 2

Given :

acceleration = 1 m/s sq.

distance ( s ) = 25 m

initial value ( u ) = 0 m

Find :

final value ( v ) = ?

Solution :

${v}^{2} = {u}^{2} + 2as \\ \\ {v}^{2} = {0}^{2} + 2 \times 1 \times 25 \\ \\ {v}^{2} = 0 + 50 \\ \\ {v}^{2} = 50 \\ \\ v = \sqrt{50} \\ \\ v = 7.07 m/s .$