Question

a biker accelerates at a rate pf 3.2 m/s2. how long will it take the biker to reach a speed of 18 m/s?

Answer 1

here is the solution,
acceleration of the bike=3.2m/s2
v=18m/s
let u=0
then, by using first equation of motion:
v=u+at
18=0+3.2*time
This implies,
time=18/3.2 seconds
time=3.675 seconds

Thus, the bike takes 3.675 to reach the speed of 18 m/s..

thanks for questioning..