Question

A biker at rest sees a bus 1km ahead of him moving with a constant speed of 10ms 1. With what constant speed should he move so as to overtake
the bus in 100s?
(A) 10ms 1
(B) 50ms -1
(C) 30ms 1
(D) 20ms 1​

Answer 1

Answer:

Given,

t = 100s,

s = 1000m;

v = 10m/s.

10 = Vs-10;

So,

Vb = 20m/s

Answer 2

Answer:-

20m/s

Explanation:-

Distance covered by bus in 100s is

=10×100=1000m

Hence , the distance between scooter and bus

after 100s will be

=1000+1000

=2000m

Speed of scooter to overtake the bus will be

➡️

$\frac{2000}{100}$

= 20m/s

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