Question

a biker passes a lamppost at the crest of a hill at 4.5 m/s. she accelerates down the hill at a constant rate of 0.40 m/s^2 for 12 seconds. how far does she move down the hill during this time?

Answer 1

Answer:

She will move 82.8m down the hill.

Explanation:

We will here use simple formula

s = ut + ${1} / {2} a {t} ^ {2}$

u = 4.5 m/s

t = 12s

a = 0.4m/s^2

s = (4.5) * (12) + ${1} / {2} (0.4) {12} ^ {2}$

= 82.8m

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