Math, asked by aryanram790, 1 month ago

(a) Bimal secured 750 marks out of a total of 900. What percentage of marks did

(b) The price of a TV decreases from 19900 to 19000. Find the decrease per cent in the he secure? price of the TV.

(c) The number of students in a school increased from 800 to 860. What was the increase per cent in the number of students?

(d) In a school, out of a total of 1050 students, 210 are girls. What per cent of the students are boys?


please answer all the question​

Answers

Answered by shp2060
0

Step-by-step explanation:

(a) Marks secured by Bimal= 750

Total marks= 900

% of marks he secured= (marks secured by Bimal/total marks)×100 %

=[(750/900)×100]

=83.33%

(b) Old price of the TV= 19900

New or decreased price of the TV= 19000

The decreased % in the price of the TV=

(decrease in the price of the TV/old price of the TV) × 100

= [(19900-19000)/19900] ×100 %

= 4.523%

(c) The number of students in a school before increase= 800

the number of students in a school after increase= 860

increase %=[ {(860-800)/860}×100]%

=[(60/860)×100]%

=6.977%

(d) total students=1050

total girls =210

total boys=(1050-210)

=840

% of the students who are boys= (total boys/total students)×100%

=[(840/1050)×100]%

=80%

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