Math, asked by arif1677272, 2 months ago

A bin contains 4 red balls and 9 blue balls. Several balls are drawn from the bin. Given that the 6th ball drawn is blue, what is the probability that the 8th ball drawn is red?

Answers

Answered by 990kjy
0

Answer:

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Answered by amitnrw
1

Given   A bin contains 4 red balls and 9 blue balls.

Several balls are drawn from the bin.

Given that the 6th ball drawn is blue,

To Find : the probability that the 8th ball drawn is red

Solution:

Red = 4

Blue = 5

Case is like this :

1     2    3    4     5     B      7      R    

So we have  6 balls   before   8

R = max 3  ( as 4th red has to be at 8th place )   and  Blue  =  8  available

out of 3 red 0 , 1 , 2 or 3 can be selected before 8th  

case 1 :   0  Red    6 blues   =  ( ⁸C₆.³C₀/¹¹C₆) * (4/6)  = (28/462) (4/6)

case 2  : 1   Red  ,  5 Blues =  ( ⁸C₅.³C₁/¹¹C₆)  * (3/6)  = (168/462) (3/6)

Case 3 : 2  Red   4  blues =  ( ⁸C₄.³C₂/¹¹C₆)   *  (2/6) =  (210/462) (2/6)

case 4  :  3 Red   3 Blues  =  ( ⁸C₃.³C₃/¹¹C₆)  * (1/6)  =  (56/462) (1/6)

(28/462) (4/6) + (168/462) (3/6) + (210/462) (2/6) +   (56/462) (1/6)

(112 + 504 + 420 + 56) / (2772)

= (1092) /2772

= 13/33

= 0.394

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