A binary solid a+ b- has zns a+ occupy the tetrahedral holes the formula is
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Explanation:
Let the number of ions be 'N'.
We know that if the number of particles is 'N', the number of tetrahedral voids will be 2N.
However, ions are occupying only 25% of the tetrahedral holes. This means that the number of ions will be 25% of 2N, i.e., (1/4)*2N which is equal to N/2.
Therefore, the formula of the solid will be:
A - N/2
B - N
Multiplying both by 2, the formula of the solid becomes
A - N
B - 2N
Now, we can cancel out N present in both A and B. Thus, the formula of the solid will be AB
Hence, (c) will be the correct option.
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