Question

A binary solution contains 4 mol of A and 6 mol of B.Its vapour pressure is found to be 460mm Hg.To this solution,when 10 mol of B is added,its vapour pressure becomes 480mm Hg.The vapour pressures of pure A and pure B,respectively,are

Answer 1

यझभचणचमचय यजहंभझबभथतथह णजभछबजमजयजःयछ

Answer 2

Answer:

pA= 96mmHg

pB= 384 mmHg

Explanation:

concept- initial mole fraction of A and B in liquid solution is 0.4 and0.6 respectively

(mole fraction = na/na+nb)

vapour pressure initial = pi

Addition of 10 mole of B is added then mole fraction of A and B become 0.2 and 0.8 respectively

vapour pressure final= pf

vapour pressure of A = pA

vapour pressure of B = pB

pA= Xa* pf

pA= 0.2*480= 96mmHg

pB= Xb* pf

pB= 0.8* 480

pB= 384 mmHg

#SPJ2