Question

A(binding energy=5) reacts with B(BE=6) to form C(binding energy=3) and D(BE=4) A + B  C + D + Energy Energy given out is
a. 4 units
b. -4 units
c. 0 unit
d. None of these​

Answer 1

Answer: Energy given out is -4 units.

Explanation: In this we need to find out the Energy Released during the reaction and we know that energy released is equals to Q-value. Therefore,

GIVEN :

The binding energy of A = 5

The binding energy of B = 6

The binding energy of C = 3

The binding energy of D = 4

Now, the reaction is given as,

A + B => C + D + Energy given out

TO FIND :

The ENERGY RELEASED we need to firstly find out the Q-value as,

Energy released = Q-value

SOLUTION :

Q-value = Binding energy of Products - Binding energy of Reactants

Now, let us find out the BE of Products,

BE of products = C + D

Now putting the value of C and D, we get,

BE of products = 3+4

BE of products = 7

Now, let us find out the BE of Reactants,

BE of Reactants = A + B

Now putting the value of A and B, we get,

BE of Reactants = 5 + 6

BE of Reactants = 11

Now, let us put the values of BE of Reactants and products in the above formula of Q-values, we get,

Q-value = Binding energy of Products - Binding energy of Reactants

Q-value = 7 - 11

Q-value = -4 units

ANSWER : the energy given out is -4 units.