A bird flies at 9.2 m high with a velocity of 10 m/s. Find the ratio of its potential energy to its kinetic energy.
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Answered by
7
Given conditions ⇒
Height to which the bird is raised = 9.2 m.
Velocity of the bird = 10 m/s.
Potential Energy = mgh
Kinetic Energy = 1/2 mv²
∴ Ratio of the Potenatial and kientic enrgy = P.E./K.E.
= mgh/1/2 mv²
= 2gh/v²
= 2 × 10 × 9.2/100
= 184/100
= 92/50
= 46/25
= 46 : 25
Hope it helps.
Answered by
4
Given,
A bird flies = 9.2 m
velocity = 10 m/s
potential energy = mgh
=> 9.2 × 10
=> 92m
kinetic energy = 1/2 × mv^2
=> 1/2 × 10× 10
=> 50m
Ratio of the potential energy and kinetic energy :-
92 : 50
simplyfying decided by 2
46 :25 Ans
A bird flies = 9.2 m
velocity = 10 m/s
potential energy = mgh
=> 9.2 × 10
=> 92m
kinetic energy = 1/2 × mv^2
=> 1/2 × 10× 10
=> 50m
Ratio of the potential energy and kinetic energy :-
92 : 50
simplyfying decided by 2
46 :25 Ans
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