A bird flies for 4 s with a velocity of (t-3) m/s in a straight line, where tis in second. The distance travelled by the bird in 4 second is.
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Explanation:
Velocity, u=∣t−2∣
Time, t=4 s
at t=0, u=2 m/s
t=2, u=0 m/s
t=4 ,u=2 m/s
between time t=0 to t=2sec
a=
2
0−2
=−1 m/s
2
s
1
=ut+
2
1
at
2
s
1
=2×2+
2
1
×(−1)×4=2
Between time t=2 to t=4sec
a=
2
0−2
=1 m/s
2
s
2
=
2
1
×1×4=2
Thus,
Total distance;
s
1
+s
2
=2+2=4 m
Thus, during the 4 seconds, the bird travels a distance of 4 m.
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