Question

A bird flies from a tree A to the tree B with the speed of 40 km h–1 and returns to tree A from tree B with the speed of 60 km h–1. What is the average speed of the bird during this journey?

Answer 1

Answer:

48 km/h

Explanation:

2÷(1/v1+1/v2)

=2÷(1/40+1/60)

=2÷{(60+40)/2400}

=2÷(1/24)

=48

Answer 2

The average speed of the bird during the course of the journey between both the trees A and B is 50 km h-1.

The average speed is given as the speed that the bird should have constantly maintained so that it could have completed the journey in the exact same amount of time, instead of flying at two different speeds. It is given by the average of the two speeds, when the distance traveled is the same. The average of the given speeds comes out to be 50 km h-1.