Question

a bird flies north at 20m/s for 15sec.it rests for 5sec and then flies south at 25m/s for 10sec.for the whole journey of the bird find(a)average speed(b)average velocity.

Answer 1

(a) Total distance travelled = 20*15 + 25*10 = 550
Average speed = Total distance travelled/ Total time taken
= 550/ 15+5+10
= 55/3 m/s

(b) Total displacement = 20*15 - 25*10 = 50
Average velocity = 50/30 = 5/3 m/s

Hope it helps
Mark as brainlist plz

Answer 2

Answer:

As per your question:

Given bird flies north : V 1 = 20m/s for t1= 15sec

distance = 300m [d1]

now d2 = 0 as v2=0 for t2=5s

now V3 = 25m/s for t3=10s

TOTAL DISTANCE = v1t1 +v2t2 +v3t3 = 300m +250m = 550m

total time = 15+5+10 = 30sec

Displacement = d1 - d3 = 300 - 250 = 50 m

Average velocity = 50/30 =1.66m/s

Average acceleration = -1.5m/s2

Explanation:

pls support me