a bird flies north at 20m/s for 15sec.it rests for 5sec and then flies south at 25m/s for 10sec.for the whole journey of the bird find average accleartion
Answers
Answered by
1
Given bird flies north : V 1 = 20m/s for t1= 15sec
distance = 300m [d1]
now d2 = 0 as v2=0 for t2=5s
now V3 = 25m/s for t3=10s
TOTAL DISTANCE = v1t1 +v2t2 +v3t3 = 300m +250m = 550m
total time = 15+5+10 = 30sec
Displacement = d1 - d3 = 300 - 250 = 50 m
Average velocity = 50/30 =1.66m/s
Average acceleration = -1.5m/s2
3.5K viewsView 1 Upvoter
Sponsored by INDmoney
distance = 300m [d1]
now d2 = 0 as v2=0 for t2=5s
now V3 = 25m/s for t3=10s
TOTAL DISTANCE = v1t1 +v2t2 +v3t3 = 300m +250m = 550m
total time = 15+5+10 = 30sec
Displacement = d1 - d3 = 300 - 250 = 50 m
Average velocity = 50/30 =1.66m/s
Average acceleration = -1.5m/s2
3.5K viewsView 1 Upvoter
Sponsored by INDmoney
Answered by
1
Answer:
now I have answered your questions so please mark my answer as brainliest
Attachments:
Similar questions