Question

A bird flies with an average velocity of 7.5 m/s east from one branch to another in 2.4 s. It then pauses before flying with an average velocity of 6.8 m/s east for 3.5 s to another branch. What is the bird’s total displacement from its starting point? a.42 m west b.6 m west c.6 m east d.42 m east

Answer 1

Answer:

7.5/2.4=3

6.8/3.5=2

42/6=7 ans

Answer 2

Given:

Average velocity for flying from the first branch to the second branch

$v_{1}$ = 7.5 m/s

Time taken for flying from the first branch to the second branch

$t_{1}$ = 2.4s

Average velocity for flying from the second branch to the third branch

$v_{2}$ = 6.8 m/s

Time taken for flying from the second branch to the third branch

$t_{2}$ = 3.5s

To find:

We have to find the total displacement of the bird between the starting and ending point.

Solution:

The relation between displacement, velocity, and time is given by,

$\[s = v \times t\]$

where

s - displacement

v - velocity

t - time

Displacement between first and second branch

= $\[v_{1}\times t_{1}\]$

= $\[7.5\times 2.4\]$

= 18 m

Displacement between second and third branch

= $\[v_{2}\times t_{2}\]$

= $\[6.8\times 3.5\]$

= 23.8 m

Since the bird travels in the same direction (east) both times, we can add the two displacements to get the total displacement.

Total displacement = 18 + 23.8 = 41.8 m which can be rounded off to 42 m.

The total is displacment is 42m east.