Question

A bird in air (µ of air=1.0) is at a height of 20 m from the surface of water. A fish is at a depth 10 m below the surface of water (µ of water=4/3). Find the apparent distance between the fish and the bird. (Real depth/ apparent depth = refractive index)​

Answer 1

Answer:

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Explanation:

A bird in air (µ of air=1.0) is at a height of 20 m from the surface of water. A fish is at a depth 10 m below the surface of water (µ of water=4/3). Find the apparent distance between the fish and the bird. (Real depth/ apparent depth = refractive index)