a bird is flying at a height of 2.4 m above the surface of water and a fish is in the water at a depth of 1.2 M. The apparent distance of the fish to the bird is
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answer : 3.3 m
explanation : the fish is appearing in water (i.e., denser medium) while the bird is flying 2.4m above the surface of water (i.e., in rare medium).
refractive index of water, μ = 4/3
use formula,
real depth of fish in water from the surface of water/apparent depth = μ
or, 1.2m/apparent depth = 4/3
or, apparent depth = 1.2/(4/3) = 0.9m
now, apparent distance of fish to the bird = height of bird from the water surface + apparent depth of fish
= 2.4m + 0.9m = 3.3 m
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