Question

A bird is flying in air at a height of 10 m from the surface of water. A fish is at a depth of 5 m below the surface of water. The refractive index of water is 4/3. The apparent distance of the fish from the bird is

Answer 1

Answer:

refractive index =real depth/apparent

depth4/3=real depth/ 30

[4×30]/3=real depth

real depth=4×10=40cm

Explanation:

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