Physics, asked by aamerisfaith, 10 months ago

A bird is flying to the right when a gust of wind causes the bird to accelerate leftward at 0.5\,\dfrac{\text m}{\text s^2}0.5
s
2

m
​ 0, point, 5, space, start fraction, m, divided by, s, start superscript, 2, end superscript, end fraction for 3\,\text s3s3, space, s. After the wind stops, the bird is flying to the right with a velocity of 2.5\,\dfrac{\text m}{\text s}2.5
s
m
​ 2, point, 5, space, start fraction, m, divided by, s, end fraction.
Assuming the acceleration from the wind is constant, what was the initial velocity of the bird before the gust of wind?

Answers

Answered by nidaeamann
0

Answer:

initial velocity of the bird before the gust of wind =  4 m/s

Explanation:

Let us first restate question statement;

A bird is flying to the right when a gust of wind causes the bird to accelerate leftward at 0.5 m/s^2 for 3 s. After the wind stops, the bird is flying to the right with a velocity of 2.5 m/s.

Assuming the acceleration from the wind is constant, what was the initial velocity of the bird before the gust of wind?

Now coming to the solution; Let us say Initial Velocity of Bird = U m/s

Final Velocity of Bird V = 2.5 m/s

acceleration a = -0.5 m/s²  ( as opposite to the fly direction)

Time T= 3 sec

Applying equation of motion

V = U + aT

=> 2.5 = U + (-0.5)3

=> 2.5 = U -1.5

=> U = 4 m/s

Hence the initial velocity of the bird before the gust of wind =  4 m/s

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