Question

A bird is flying with a speed of 40 km/h in the north direction. A train is moving with a speed of 30 km/h in the west direction. A passenger sitting in the train will see the bird moving with velocity : (1) 50 km/h in N-E direction (2) 40 sqrt 2 km/h in N - E direction (3) 40 km/h in N-W direction (4) 40 sqrt 2 km/h in N-W direction (with explanation)​

Answer 1

40

2

km/hr in N-E direction

v

bt

=

v

b

−

v

T

⇒

v

bT

=40

j

^

+40

i

^

⇒∣

v

bT

∣=40

2

km/h

tanθ=

40

40

=1⇒θ=45

∘

Direction ⇒N−E