A bird is flying with velocity (2i+3j-k) ms^-1 the angle made by the velocity with y axis is
Answers
Answer:
Cos^(-1) (3/√14) = theta
Explanation:
velocity of bird =(2i+3j-k)
longest diognal / hypotenous=√x^2+y^2+z^2 = √4+9+1= √14
therefore angle made by velocity with y axis
cos teta =3/√14
teta = cos^-1 (3/√14)
The angle made by the velocity with y axis is
Explanation:
Given:
A bird flying with velocity (2i + 3j + k ) m/s
To find: The angle made by velocity with y axis
Solution:
The velocity is (2i + 3j + k ) m/s
We want to find the angle for the given vector makes with the y axis.
i.e the unit vector j.
The product of the two unit vectors is the cosine of the angle between them.
The unit vector in the direction of A is
⇒
=
=
The cosine of the angle between the two vector is
⇒ =
⇒ The angle that the vector makes with the y axis is
Final answer:
The angle made by the velocity with y axis is
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