Physics, asked by taanuranga1866, 1 year ago

A bird is flying with velocity (2i+3j-k) ms^-1 the angle made by the velocity with y axis is

Answers

Answered by azaziabdullah207207
2

Answer:

Cos^(-1) (3/√14) = theta

Explanation:

velocity of bird =(2i+3j-k)

longest diognal / hypotenous=√x^2+y^2+z^2 = √4+9+1= √14

therefore angle made by velocity with y axis

cos teta =3/√14

teta = cos^-1 (3/√14)

Answered by aburaihana123
1

The angle made by the velocity with y axis is cos (\frac{\sqrt{3} }{14} )

Explanation:

Given:

A bird flying with velocity (2i + 3j + k ) m/s

To find: The angle made by velocity with y axis

Solution:

The velocity  is (2i + 3j + k ) m/s

We want to find the angle for the given vector makes with the y axis.

i.e  the unit vector j.

The product of the two unit vectors is the cosine of the angle between them.

The unit vector in the direction of A is \frac{A}{|A|}

\frac{2i +3j +k}{|2i+3j+k|}

= \frac{2i +3j +k}{\sqrt{14} }

= \frac{2}{\sqrt{14} } i +\frac{3}{\sqrt{14} } j+\frac{1}{\sqrt{14} } k

The cosine of the angle between the two vector is

(\frac{2}{\sqrt{14} } i +\frac{3}{\sqrt{14} } j+\frac{1}{\sqrt{14} } k)j  = \frac{3}{\sqrt{14} }

⇒ The angle that the vector 2i + 3j + k makes with the y axis is cos (\frac{\sqrt{3} }{14} )

Final answer:

The angle made by the velocity with y axis is cos (\frac{\sqrt{3} }{14} )

#SPJ3

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