A bird is sitting on the floor of a closed glass cage and the cage is in the hand of a girl. Will the girl experience any change in the weight of the cage when the bird (i) starts flying in the cage with a constant velocity (ii) flies upwards with acceleration (iii) flies downwards with acceleration?
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Answered by
12
Very good question. Thanks for asking it.
1] starts flying in the cage with a constant velocity :
constant velocity means acceleration is zero.
There is no change in weight of the age
ii)flies upwards with acceleration:
Reaction force is :R=m(g+a)
Thus age will appear heavier than before.
iii)) flies downwards with acceleration:
In this case reaction force:R=m(g-a)
Thus age will appear lighter than before.
1] starts flying in the cage with a constant velocity :
constant velocity means acceleration is zero.
There is no change in weight of the age
ii)flies upwards with acceleration:
Reaction force is :R=m(g+a)
Thus age will appear heavier than before.
iii)) flies downwards with acceleration:
In this case reaction force:R=m(g-a)
Thus age will appear lighter than before.
Answered by
0
Answer:
(i)No
(ii)Yes
(iii)Yes
Explanation:
In a closed glass cage , air inside a bound with the cage .
Therefore,
(i)there would be no change in weight of the cage if the bird flies with a constant velocity.
(ii)the cage becomes heavier, when bird flies upwards with an acceleration.
(iii)the cage appears lighter , when bird flies downwards with an acceleration.
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