A bird is sitting on the top a tree which is 90m. the angle of elevation of the bird, from a
point on the ground is 60°. The bird flies away from the point of observation horizontally
and remains at a constant height. After 3 sec the angle of elevation becomes 45°. Find
the speed of flying the bird.
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in triangle ABC
tan60= P/B
tan60=90/B
√3= 90/B
B = 90/√3
B = 30√3
so, AC=30√3
in triangle AED
tan45= 90/B
1/√2 = 90/ B
B= 90√2
so, AD = 90√2
AD - AC = CD
90√2 - 30√3 = 60√6
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