a bird is sitting on the top of a tree which is 80m high. the angle of elevation of the bird from a point on the ground is 45 degree . the bird fly away from the point of observation horizontal and remains at a constant height. after 2 sec covering a distance of 58.56 m the angle of elevation of the bird from the point of observation becomes teta. based on the figure find the angle of elevation of the bird from the point of observation becomes teta. based on the figure related to the above information answer the following question.
1 find the angle teta if distance of the bird from the point of observation is 160m.
2 find the speed of the bird.
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Answer:Step-by-step explanation.
(1)
In triangle DBE
p/h = sin teta
80/160 = sin teta
sin teta = 1/2
Sin teta = sin 30 degree
Therefore teta= 30 degree
(2)
Speed of bird = distance/ time
Speed of bird = 58.56/2
Speed of bird =29.28 m/s
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