A bird is tossing (flying to and fro) between two cars moving towards each other on a straight road. One car has a speed of 18 m/h while the other has the speed of 27km/h. The bird starts moving from first car towards the other and is moving with the speed of 36km/h and when the two cars were separted by 36 km. What is the total distance covered by the bird? What is the total displacement of the bird?
Answers
Answered by
52
Thank you for asking the question!
In order to find the distance covered by the bird we will suppose an equation.
Take x so, 18x + 27x = 36.
we will further solve this equation according to algebraic rules. So we will add x terms.
= 45x = 36
x= 36\45
x= 0.8
So in order to find the total distance covered by a car with the speed of 18Km per hr= 18 * 0.8km
= 14.4km
Hence the total displacement covered by a car is 14.4km.
Hope it helps
In order to find the distance covered by the bird we will suppose an equation.
Take x so, 18x + 27x = 36.
we will further solve this equation according to algebraic rules. So we will add x terms.
= 45x = 36
x= 36\45
x= 0.8
So in order to find the total distance covered by a car with the speed of 18Km per hr= 18 * 0.8km
= 14.4km
Hence the total displacement covered by a car is 14.4km.
Hope it helps
Answered by
30
Answer:
Relative speed of cars = 45km/h
Time required to meet 36/45 = 0.8 hours
Thus, distance covered by the bird = 36 km/h × 0.8h = 28.8 km.
Explanation:
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